Question

Two buildings are facing each other on a road of width 12 metres. From the top of the first building which is 10 metres high, the angle of elevation of the top of the second is found to be 60°. What is the height of the second building?​

Answer 1

Answer:

here is your solution.

Answer 2

Answer:(10+12 root 3)

Step-by-step explanation:

Let ab be the building of height 10metre

So AE is horizon

And DC is second building

Width of road isBC of 12m

Angle DAE =60Degree

Quadrilateral ABCE is rectangle

In right angle triangle DAE

Tan 60=DE/AE

Therefore answer on solving is DE=12root3metre

Now,

DC=DE+CE

DC=12root3+10

DC=(10+12 root 3)metre