Question

two buildings are facing each other on a road of width 12 m. from the top of the first building which is 10m high the angle of elevation of the top of the second is found to be 60 what is the height of second building​

Answer 1

Answer:

30.78

Explanation:

Let AB be the small building and CD be the tall building.

∴ED=BA=10 m

Let CE=x

In △BCE,

tan60=

BE

CE

⇒

3

=

12

CE

⇒CE=12

3

⇒CE=20.78 m

Hence.

CD=CE+ED

CD=20.78+10

CD=30.78 m

Thus, height of the second building will be 30.78 m