Question

Two buildings are facing other on a road of width 5 m .from the top of the first building which is 2 m high, the angle of elevation of the top of the second building is found to be 30’.What is the height of the second building?

Answer 1

Answer:

The answer and the step by step procedure is as follows hope it helps you

Step-by-step explanation:

Let AB and CD be two building, with

AB = 10 m

And angle of elevation from top of AB to top of CD = ∠CAP = 60°

Width of road = BD = 12 m

Clearly, ABDP is a rectangle

With

AB = PD = 10 m

BD = AP = 12 m

And APC is a right-angled triangle, In ∆APC

⇒ CP = 12√3 m

Also,

CD = CP + PD = (12√3 + 10) m

Hence, height of other building is (10 + 12√3 m).