Question

Two buildings are in front of each other on a road of width
top of the first building, having a height of 12 meter, the angle of
ther on a road of width 15 meters. From the
of 12 meter, the angle of elevation of the
second building is 30° What is the height of the second building!
ton ongle of​

Answer 1

As shown in the figure, suppose AB and CD are the buildings.

Distance between AB and CD is 15 m.

Angle of elevation at point C is 30˚.

∠ECA = 30˚

EC ⊥ AB.

BD = 15 m.

∴ EC = 15 m.

CD = 12 m.

∴ BE = 12 m.

In ∆AEC,

tan30 = AE / EC

∴ 1 / √3 = AE / 15

∴ √3 x AE = 15

∴ AE =15 /√3 x √3 / √3 =5 √3

Height of the second building = BE + AE = (12+5 √3 )m.

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