Two buildings are in front of each other on either side of road of width 10m . From the top of first building, which is 30 m high,the angle of elevation of top the second is 45degrees . what is the height of the second building?
Answers
answer is 40 m for ur ques.
QUESTION:
Two buildings are in front of each other on either side of a road of width 10 metres. From the top of the first building, which is 30 metres high, the angle of elevation of the top of the second is 45º. What is the height of the second building ?
ANSWER:
Let AB be the height of the first building, CD be the height of the second building,
∴ AB = 30 m,
BD be the width of the road,
∴ BD = 10 m,
∠ CAE = 450,
□ ABDE is a rectangle,
AB = DE = 30 m [Opposite sides of rectangle]
BD = AE = 10 m
In right angled ∆CEA,
tan 450 = Opposite side of 450 / Adjacent side of 450
∴ 1 = CE/ AE
∴ 1 = CE/10
∴ CE = 10 m
CD = CE + ED [∵ C - E - D]
∴ CD = 10 + 30
∴ CD = 40 m
∴ The height of second building is 40 m.
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