Question

Two buildings are in front of each other on either side of a road of which 10 metres. From the top of the first building which is 40 metres high, the angle of elevation to the top of the second is 45°. What is the height of the second building?
(PLEASE SOLVE THIS QUESTION PLEASE)​

Answer 1

Step-by-step explanation:

Solution To Question

Answer

In the fig., AB and CD represent two building.

∴AB=30 m

BD is the width of the road

∴BD=10 m

∠CAE is the angle of elevation.

∴∠CAE=45

∘

Draw seg AE∥seg BD meeting seg CD at point E

□ABDE is a rectangle

∴AE=BD=10 m

and AB=ED=30 m

Let CD=x

In right angle △AEC,

tan45 = AECE

1= 10x

∴x=10 m

∴CE=10 m

Now, CD=CE+ED=10+30=40 m

Thus, the height of the second building is 40 metre.