Question

Two bulb B1 and B2 are connected in series with an AC source 200V,as shown.The labels on the bulbs reads 200V-60W and 200V-100W respectively.Calculate the ratio of:(i)the power being consumed when connected in series (P1/P2),(ii)the PD across the bulbs(V1/V2)​

Answer 1

Answer:

Explanation:

Power = Voltage X Current

Voltage = Current X Resistance

P = V2/R

Bulb B1:

P= 100 W

V= 250 V

R1 = 625 ohms

Bulb B2:

P= 100W

V= 200V

R2= 400 ohms

Total Current = V'/ (R1+R2)

Here, V' = 250V (Main voltage supply)

R1+R2= 1025 ohms

I= 250/1025 = 0.244 A

Potential difference across B1 = I X R1 = 0.244 X 625 = 152.5 V

Potential difference across B2 = I X R2= 0.244 X 400 = 97.6 V