Question

two bulbs 200v 100w at 110v are connected to a voltage source of 400v the ratio of resistance of 2 bulbs is

Answer 1

Answer:

ANSWER

R

1

=

P

v

2

=

25

200

2

=1600Ω

R

2

=

100

200

2

=400Ω

When both bulbs are connected in series

V

1

=440×

R

1

+R

2

R

1

=440×

1600+400

1600

=352V;V

2

=440×

2500

400

=88V

Voltage across 25W bulb is greater than specified voltage, hence it will fuse..

Explanation:

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