Question

two bulbs 60w,220 volt and 100w ,220 volt are connected in series to a 440 volt supply . a. which of the two bulb fuse ? b. what happens if this bulbs are connected in parallel ?​

Answer 1

Answer:

Power, P=V

2

R

R

1

=

50

220×220

=968Ω

R

2

=

100

220×220

=484Ω

The equivalent resistance in the circuit,

R

eq

=R

1

+R

2

R

eq

=968+484=1452Ω

The current flow in the circuit,

I=

1452

440

=0.3030A

The voltage drop across bulb 1.

V

1

=iR

1

=0.3030×968=293.33V

The voltage drop across bulb 2.

V

2

=iR

2

=0.3030×484=

Answer 2

Step-by-step explanation:

your answer is 968∆ okkkkkkkkkkkkkkkkkkkkkkkk