Question

two bulbs a & b consume same power P when operated at voltages V1 & V2 respectively. If these bulbs are connected in series across a d.c. source, then find the ratio of potential difference across A & B​

Answer 1

Answer:

I hope it help you.......

Answer 2

Answer:

The ratio of potential difference across A & B​ is 4/9.

Explanation:

• A voltage is the pressure of an circuit which is a electrical of the power source that can push a charged electrons that is current through the loop of conduction.
• It helps in enabling to work on a light that is illuminating.
• It is measured by:

Voltage = pressure

Here it is measured also with volts (v).

There are three types of voltages. They are:

1) High voltage: it is 115, 000 to 1,100, 000 VAC

2) Medium voltage: It is 2,400 to 69,000 VAC

3) Low voltage: It is 240 to 600 VAC

• Example of the voltage:

When there is specific amount of electricity that is available in the circuit.

A D.C source is defined as the electrical energy which can be used along with voltages of constant and currents.

Given that:

Two bulbs a and b that consume same power P.

It operates at voltages v1 and v2.

To find:

Ratio of potential difference across A and B =?

Solution:

Let us consider,

R1 = 200 , R2 = 300

By putting these values,

R1 = $(200^{2} ) / p$

R2 =$(300^{2}) /p$

$V_{1} / V_{2}$= $R_{1} ^{2}$/  $R_{2} ^{2}$ = 400/900

                                = 4/9

Therefore,

P1 / P2 =$i2 R_{1}$ / $i2 R_{2}$

R1/R2 = 4/9

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