two bulbs, A &B rated 220volt - 100 watt respectively are connected across are 220 volt source in parallel. calculate the current through each bulb, which consume more power
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Answer:
Explanation:
P=
R
V
2
⇒V
A
=
P
V
2
=
40
220×220
=1210Ω
R
B
=
60
220×220
=806.67Ω
In this case, the applied voltage across the series combination itself is 220V, the rated voltage of both the bulbs.
As a result, potential difference across the bulbs will not exceed the rated value.
At the same time, current through each bulb will be the same.
Hence, the bulb with greater resistance will glow brighter (since I
2
R will be greater).
Resistance of bulb A> resistance of bulb B.
Therefore, A burns brighter than B.
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