Physics, asked by lokesh818, 10 months ago

Two bulbs A and B are rated as 60 W -120 V and 100 W – 120 V respectively. They are connected in parallel across a 120 V source. Find the current in each bulb. Which bulb will consume more energy? Please answer the question

Answers

Answered by aadesh1257

so,Resistance{R}=

so,Resistance{R}= P

so,Resistance{R}= Pv

so,Resistance{R}= Pv 2

so,Resistance{R}= Pv 2 =

so,Resistance{R}= Pv 2 = 100

so,Resistance{R}= Pv 2 = 100220

so,Resistance{R}= Pv 2 = 100220 2

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)=

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= R

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv 2

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv 2 =

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv 2 = 645.33

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv 2 = 645.33220

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv 2 = 645.33220 2

so,Resistance{R}= Pv 2 = 100220 2 =484Ω.on solving the equivalent resistance of the circuit we find R equivalent =645.33Ω.therefore total power across the circuit will be(P)= Rv 2 = 645.33220 2 =75watt

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