Question

Two bulbs A and B of equal capacity contains 10g of oxygen (O2)and ozone respectively. which bulbs will have (i).Larger number of molecules?
(ii).larger number of oxygen atoms. ​

Answer 1

Explanation:

10 g O2 = 10 / 32 mole O2 = .3125 mole

10 g O3 = 10 / 48 mole O3 = .2083 mole

So 10 g of O2 contains (.3125 × Navo) no molecules whereas 10 g of O3 contains (.2083 × Navo ) no molecules.

As O2 is diatomic , 10 g of O2 = (2 × .3125 × Navo ) = (.6250 × Navo) no O atom

As O3 is triatomic , 10 g of O3 = ( 3 × .2083 × Navo ) = ( .6249 × Navo ) no of 0 atoms

As both are same upto 3 significant number , B1 & B2 both have equal no of O atoms . But B1 has greater no of molecules .