two bulbs A is marked 55W, 110V and B is marked 100W 240v (a) Which among the above bulbs has higher resistance (b) Find the power of bulb B when the applied voltage is reduced to 120V
Answers
Answered by
10
Answer:
(a) B bulb which is marked as 100W 240v has the higher resistance
(b) 100W
Explanation:
use the formula of power P=V^{2} / R
Answered by
0
Answer:
(a)B has higher resistance
(b)P=25 W
Explanation:
A -55W,110V
B -100W,240V
(a)A R1=V2÷P
= 110×110÷55
=12100÷55
= 220Ω
B R2=V2÷P
= 240×240÷100
= 576Ω
220<576
Therefore,B has the higher resistance (576Ω)
(b) P=V2÷P
=120×120÷576
=25W
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