Two bulbs are connected in series. The first bulb has power 50 Watts and PD 220 volts and second bulb has power 100 Watts and PD 220 volts are connected to circuit having PD of cell is 440 volts which bulb get fuse, give explanation ?
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pls solve this question important one
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sdey1498:
Hey mate! the question is not clear
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50 watts bulb will fuse earlier than the 100 watts bulb.
As we know that,
Resistance= Voltage^2 / Power
And we see both the bulbs has a voltage rating is 220 Volts. , hence voltage remains constant in both the cases.
Now, the bulb which has lower power rating will have higher resistance.
But,
As per the question both the bulbs are connected in series. Hence, both the resistances will add into one.
In series connection, the equipment with higher resistance have to bear more Voltage. So, the 50Watts bulb will fuse first.
As we know that,
Resistance= Voltage^2 / Power
And we see both the bulbs has a voltage rating is 220 Volts. , hence voltage remains constant in both the cases.
Now, the bulb which has lower power rating will have higher resistance.
But,
As per the question both the bulbs are connected in series. Hence, both the resistances will add into one.
In series connection, the equipment with higher resistance have to bear more Voltage. So, the 50Watts bulb will fuse first.
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