Physics, asked by jyotiradityakedia9a2, 2 months ago

Two bulbs are marked 100 W, 220 V and 60 W, 110 V. Calculate
the ratio of their resistances.

Answers

Answered by tarushi9
0

Answer:

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Answered by Anonymous
1

Answer:

Power, P=V2R

R1= 220×220/50

=968Ω

R2 = 220×220/100

=484Ω

The equivalent resistance in the circuit,

Req =R1 +R2

Req =968+484=1452Ω

The current flow in the circuit,

I= 440/1452

=0.3030A

The voltage drop across bulb 1.

V1=iR1 =0.3030×968=293.33V

The voltage drop across bulb 2.

V2=iR2=0.3030×484=146.65V

Bulb 1 will be fused because it can tolerate only 220 V but the voltage drop across it is 293.33V

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