Question

two bulbs B1 and B2 of equal capacity contain 10 gram oxygen O2 and Ozone O3 respectively which bulb will have a greater number of atom​

Answer 1

Answer:

hope it helps☺☺

mark me brainlinest plzzzzzzz

Explanation:

we know that no. of moles = given mass ÷molar mass

so for b1 no. of moles is 10÷32

similarly for b2 no. of moles = 10÷ 48

Since 10÷32 > 10÷48 , no. of molecules in b1 is greater

now we have to find no. of atoms.

so for b1 which contains O2 has 2 atoms in 1 molecule

and b2 which contains O3 has 3 atoms in 1 molecule

Therefore

no. of atoms in b1 = 10÷32×2×NA = (10÷16)NA

and no of atoms in b2 = 10÷48×3×NA = (10÷16)NA

(NA= Avagadro no.)

Hence both b1 and b2 will have same no. of atoms.