Question

two bulbs marked 200w, 250v and 100w,250v address joined in series 250v supply. Find the power consumed by the circuit

Answer 1

Power=VoltageXcurrent

P=VI

V=250 V

let I flow through Bulb 1

and i flow through Bulb 2

Bulb(1)=B1 consumes power 200 W=P(1)

B2 consumes power 100 W=P2

for bulb 1

P(1)=VI

200/250=I=0.8 A

for bulb 2

P(2)=Vi

100/250=i=0.4 A

Now resistances in bulbs will be [R(1)and R(2)]

R(1)=V/I and R(2)=V/i

R(1)=250/0.8=312.5 ohms.

R(2)=250/0.4=625 ohms

As resistances are in series

total resistances R

R=R(1)+R(2)

R=937.5 ohms

now P=V²/R

P=(250)²/937.5=

P=66.67 W

Answer 2

P=VI

For bulb 1

200=250×I

I=0.8A

R=V/I

=250/0.8

=312.5ohm

For bulb 2

100=250×I

I=0.4A

R=V/I

=250/0.4

=625ohm

Total resistance in series

=625+312.5

=937.5ohm

Total power

=V^2/R

=250×250/937.5

=66.67

Hope it helped you

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