two bulbs of 100W each and two coolers of 250W each ,work on an average 6hours a day.if the energy costs rs 1.75.calculate the monthly bill.plz help me in this question and i will mark your answer as brainliest
Hetarth4:
enerGy cost 1.75 but for a unit ??
ya
Answers
Answered by
43
We know , power = energy / time =>energy = power × time
two bulbs = 100×2=200W per day
two coolers = 250×2=500W per day
They work 6 hour per day. So the energy consumed in 1 day :-
Bulbs = > 200×6=1200W/h=> 1.2KW/h
Coolers=>500×5=2500W/h=>2.5KW/h
Total energy consumed = 3.7KW/h
1 unit = 1KW/h
1unit cost 1.75
3.7unit =?
=>3.7×1.75=6.475rupees will ne the monthly bill
If you find it helpful please mark it as brainliest....
two bulbs = 100×2=200W per day
two coolers = 250×2=500W per day
They work 6 hour per day. So the energy consumed in 1 day :-
Bulbs = > 200×6=1200W/h=> 1.2KW/h
Coolers=>500×5=2500W/h=>2.5KW/h
Total energy consumed = 3.7KW/h
1 unit = 1KW/h
1unit cost 1.75
3.7unit =?
=>3.7×1.75=6.475rupees will ne the monthly bill
If you find it helpful please mark it as brainliest....
actually its only the question
we dont have to findthe monthly bill ?
yes we have to.
done
then whats the answer
6.475 rupees
sorry message sent by mistake
thanks for your answer i have marked it as brainliest .
welcome
Answered by
0
Answer:
6.475 rs
Explanation:
We know , power = energy / time =>energy = power × time
two bulbs = 100×2=200W per day
two coolers = 250×2=500W per day
They work 6 hour per day. So the energy consumed in 1 day :-
Bulbs = > 200×6=1200W/h=> 1.2KW/h
Coolers=>500×5=2500W/h=>2.5KW/h
Total energy consumed = 3.7KW/h
1 unit = 1KW/h
1unit cost 1.75
3.7unit =?
=>3.7×1.75=6.475rupees will ne the monthly bill
If you find it helpful please mark it as brainliest....
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