Question

two bulbs of 40W-110V ,60W-110V,are connected in parallel and this combination is connected to 220V supply .Which of the two bulbs fuses
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Answer 1

Answer:

Power, P=V2R

R1=50220×220=968Ω

R2=100220×220=484Ω

The equivalent resistance in the circuit,

Req=R1+R2

Req=968+484=1452Ω

The current flow in the circuit,

I=1452440=0.3030A

The voltage drop across bulb 2.

V2=iR2=0.3030×484=146.65V

Bulb 1 will be fused because it can tolerate only 220 V but the voltage drop across it is 293.33V

Explanation:

i had tried my best ..

Answer 2

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