Two bulbs of 40W each are lighted for eight hours daily. Find the cost of electrical energy consumed by then in one week at re.3 per unit.
Answers
So we have,
power of one bulb = 40 W
time = 8 hrs
Amount of electrical energy consumed in one day by the two bulbs,
= 40 × 8 × 2 / 1000
= 0.64 kWh
Amount of electrical energy consumed in one week, i.e., 7 days,
= 0.64 × 7 = 4.48 kWh
Now, the total cost of electrical energy is,
3 × 4.48 = ₹ 13.44
Dear Student,
● Answer -
Cost of electrical energy = 13.44 Rs
◆ Explaination -
Total time for lighting the bulbs is -
Time = 8 hrs daily × 7 days
Time = 56 hrs
Electrical energy consumed by one bulb in this time is -
Energy consumed = Power × Time
Energy consumed = 40 × 56
Energy consumed = 2240 Wh
Energy consumed = 2.240 kWh
Energy consumed = 2.240 units
Cost of energy consumed by 2 such bulbs is -
Cost of energy = 2 × 2.240 × 3
Cost of energy = 13.44 Rs
Therefore, cost of electrical energy consumed is 13.44 Rs.
Thanks dear. Hope this helps you...