Two bulbs , one with power 60w and other with power 100w .Which will have thicker filament
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Answered by
16
Use the formula P = VI, assume V to be a constant value
When P is 100W, Current(I) is higher
but when P = 60W, current is lower (remember that V is constant)
then use V = IR, when current is high, resistance is low
Hence 60 W bulb has a higher resistance than 100W bulb
When P is 100W, Current(I) is higher
but when P = 60W, current is lower (remember that V is constant)
then use V = IR, when current is high, resistance is low
Hence 60 W bulb has a higher resistance than 100W bulb
Anonymous:
hiiiii
Answered by
13
both the filaments are made up of same material, then we can use
RHO=R*A/l
Here, p is resistivity of material
R is resistance of the material
A is area of cross-section
L is length of the material
And we also need
P=V2/R
where P is the power
V is the voltage
R is the resistance.
We know all the required values, so when you solve these equations for Area, your will find that the more are is required for 100
watt filament and hence it is more thicker than the other.
RHO=R*A/l
Here, p is resistivity of material
R is resistance of the material
A is area of cross-section
L is length of the material
And we also need
P=V2/R
where P is the power
V is the voltage
R is the resistance.
We know all the required values, so when you solve these equations for Area, your will find that the more are is required for 100
watt filament and hence it is more thicker than the other.
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