Question

Two bullets of masses 5 g and 10g moving with velocities 10m/s and 5m/s respectively strike and penetrate into a fixed wooden block and come to rest.then the ratio of their respective distance moved in the block before coming to rest is.....

Answer 1

Answer:

1/2 mv^2=fk s

Explanation:

s1/s2 =m1v1^2/m2v2^2

5*10^-3 * 10^2/10*10^-3*5^2

=2/5

Answer 2

Answer:S1 : S2 = 2:1

Explanation:

Mass of first bullet = M1 = 5g = 5 x 10^-3 Kg

Velocity of first bullet = V1 =10 m/s

Mass of second bullet = M2 = 10g = 10^-3 Kg

Velocity of second bullet = V2 = 5m/s

Distance moved in = kinetic energy of bullet

KE = 1/2 mv^2

S1/S2 = KE1/KE2

= 1/2 x 5 x 100 / 1/2 x 10 x 25

= 2/1