Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answers
Answered by
17
let fare from A to B be x &fare from A to C be y
Therefore by the problem
2x+3y=77 --eq (1)
3x+2y=73 --eq (2)
Adding eq(1)&(2) we get
5x+5y=150
thus x+y=30 --eq (3) ×2
subtracting eq 3 from 1
we get x=13;y=17
therefore fare from A to B=13
fare from C to B =17-13=4
ASSUMPTION:there is no fixed charge with which the original fare is added
Therefore by the problem
2x+3y=77 --eq (1)
3x+2y=73 --eq (2)
Adding eq(1)&(2) we get
5x+5y=150
thus x+y=30 --eq (3) ×2
subtracting eq 3 from 1
we get x=13;y=17
therefore fare from A to B=13
fare from C to B =17-13=4
ASSUMPTION:there is no fixed charge with which the original fare is added
Answered by
5
Answer:
Rs. 13, Rs. 17
Step-by-step explanation:
Let Rs. x, be the fare of city B from city A and Rs. y, be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
∴ The answer is Rs. 13, Rs. 17
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