Two buses A and B are at positions 60 m and 160 m from the origin at time t=0. They start moving in the same direction simultaneously with uniform speed 54km/h and 36km/h. Determine the time and position at which A overtaken B
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relative distance is=160-60=100
relative speed =54-36=18km/h
Now we should find the time for bus moving in 18km/h for 100m
18km/h=5m/s
100/5=20
therefore, the answer is 20seconds
relative speed =54-36=18km/h
Now we should find the time for bus moving in 18km/h for 100m
18km/h=5m/s
100/5=20
therefore, the answer is 20seconds
Deepankar1908:
thanks but what about position
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