Two buses A ans B are moving in opposite direction with the velocity of 36km/hr and 108km/hr. Find the relative velocity of A with respect to B and total displacement between them after 60 seconds.
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Answer:
Suppose total distance is 2x km then
time taken in traveling the distance first x will be t
1
=
40
x
and the time taken in traveling the distance second x will be t
2
=
60
x
now the average velocity can be calculated as V=
total time
total distance
=
40
x
+
60
x
2x
=
40+60
2×40×60
=48Km/h
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