Two buses, bus A and bus B, both use the same bus stop.
Bus A runs every 10 minutes
Bus B runs every 14 minutes
Both buses are at the bus stop at 11 am.
What time will both busses next both be at the bus stop
Answers
Answer:
12:10 pm
Step-by-step explanation:
LCM OF TIME OF BUS A and B
Prime factorisation method
10= 2×5
14=2×7
LCM=2×5×7
= 70 minutes (1 hour 10 minutes)
The buses stopped together at 11am
They will meet again at 11am + 1hr 10 min=12:10pm
ANS:They will meet next at 12:10pm .
The time when both the buses will be at the bus stop will be 12:10 pm i.e. 70 mins after 11 am.
It is given in the question that Bus A runs every 10 minutes
so, performing the prime factorization of 10
10 = 2×5
It is given in the question that Bus B runs every 14 minutes
so, performing the prime factorization of 14
14 = 2×7
Now LCM ( lowest common factor of 14 and 10) =
2×5×7 = 70
hence, the answer to the problem will be 70 mins after 11 am which is equal to 12: 10 pm.