two buses start from karnal to delhi at 8am and 10am.speed of a bus start at 8amand speed of bus starting at 10am and speeds are 20m/sec and 25m/sec.if the distance between delhi to karnal is 200km then whattime faster bus will catch the slower train
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Therefore they will meet at 9 pm 11 min
Step-by-step explanation:
The faster bus has to cover an additional distance of 200× 1000= 200000
Let the time taken be t
Therefore 200000+ 20× t= 25×t
5t= 200000
t= 40,000s
t= 40,000÷ 60 min
t=666.66min
t= 666.66÷ 60 hr
=11.11hr from 10 am
Therefore they will meet at 9pm 11 min
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