Question

Two buses start from the same bus stand at 8:00am. One travels at 40km/h and the other at 50km/h. The second bus reaches the next stop at 10:00am. How much later will the first bus arrive ??? This a question of class 5 from book, Please explain it simple!!!

Answer 1

Answer:

 30 minutes

Step-by-step explanation:

Since the second bus travels at 50km/h and reaches it's next stop in two hours, by using the equation, speed= distance/time, you find that the total distance between the two stops is 100 km.

So If the first bus travels at 40 km/h and the distance it travels is also 100 km, by substituting these values in the previous equation, you find that the time it takes is 2.5 hours, or 2 hours and 30 minutes.

In conclusion, the first bus takes 30 minutes longer than the second bus.

Hope this helps!! (｡･∀･)ﾉﾞ

Answer 2

GIVEN :

• Speed of 1st bus = 40 km/hr.
• Speed of 2nd bus = 50 km/hr.
• Time travelled is 8 am to 10 am. So here, 10 - 8 = 2 hrs.

FORMULA :

• $\sf Time \: = \: \dfrac {distance}{speed}$
• $\sf Distance \: = \: speed \: \times \: time$

TO FIND :

• How much later will the first bus arrive ?

SOLUTION :

$\sf we \: know \: that \: 2nd \: bus \: is \: faster \: as \: compared \: to \: 1st \: bus.$

So, 2nd bus will arrive earlier than 1 st bus.

To find distance,

Using, $\sf Distance \: = \: speed \: \times \: time$

$\implies \sf 50 \: \times \: 2$

$\therefore {\boxed {\sf Distance \: = \: 100 \: km}}$

To find time,

Using, $\sf time \: = \: \dfrac {distance}{speed}$

$\implies \sf time \: = \: \dfrac {100}{40}$

$\therefore {\boxed {\sf time \: = \: 2.5 \: hrs}}$

$\therefore$ The time for 1st bus to arrive the next stop will 2.5 hrs.

$\therefore$ The bus will arrive 30 mins later at 10:30 a.m.