Two buses start from the same bus stand at 8 a.m.
One travels at 40 km/h and the other at 50 km/h.
The second bus reaches the next stop at 10 a.m.
How much later will the first bus arrive?
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here is your answer mate :
Speed of Bus A = 40 km/hr
Speed of Bus B = 50 km/hr
Time taken by Bus B = 2 hrs.
Total Distance to travel = ?
Speed = Distance/Time
Distance = Speed * Time
Distance to travel = 50 * 2 = 100 kms.
Time = Distance/Speed
Time taken by Bus A = 100/40 = 2.5 hrs
Thus, it will reach at 10:30 am
As a result, it has reached half an hour or 30 mins later than the earlier bus
kindly mark as brainliest
thank you =)
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