Two buses start from the same bus stand at 8
a.M. One travels at 40 km./h. And the other at 50 km./h. The second bus reaches the next stop at 10
a.M. How much later will the first bus arrive ?
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The time taken by the second bus to reach to the stop =(10-8)
= 2 hours
If the speed is 50 km/hr then the time taken is 2 hrs
If the speed is 1 km/hr then the time taken is (2×50) = 100 hrs
If the speed is 40 km/hr then the time taken is (100/40)= 2 hrs 20 min
∴ The first bus will reach to the stop after = (2°20'-2°00')
= 20 minutes
(Ans): The first bus will reach to the stop after 20 minutes.
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