two buses start from the same bus stand. at 8 am one travels at 40 km/h and the other at 50km/h. the second bus reaches the next stop at 10a.m .how much later will the first bus arrive?
Answers
Answered by
8
Distance = speed*time
D=50*2 (10-8)
D=100km
time=distance/speed
T=100/40
T=2.5hrs= 2hr and 30 mins
the first will take 30mins more to reach the stop
D=50*2 (10-8)
D=100km
time=distance/speed
T=100/40
T=2.5hrs= 2hr and 30 mins
the first will take 30mins more to reach the stop
Answered by
28
Answer:
8−9=4x+2x
−1=6x
−1/6=x
Hope it will be helpful ✌️
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