two buses started simultaneously towards each other from town A and B which of 480 kilometre parts it took the first was travelling from a to b 8 hours to cover the distance and II was travelling from b to a 10 hours determined when the buses will meet after starting and at what distance from a.
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speed of bus 1=480/8=60km/hr
second=480/10=48
let t be time after they meet
hence 60t+48t=480
108t=480
t=480/108 hr
t=40/9 hr
=40/9×60min
=800/3min or 16000sec
second=480/10=48
let t be time after they meet
hence 60t+48t=480
108t=480
t=480/108 hr
t=40/9 hr
=40/9×60min
=800/3min or 16000sec
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