Question

two buses starts from a bus stand with velocities10km/h and 30km/h and inclanied at60° find the distance between than after12mintues
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Answer 1

Explanation:

V₁ = 10 km/h = 50/18 m/s

v₂ = 30 km/h = 150/18 m/s

t = 12 min = 720 s

distance travelled S₁ = 50/18 x 720 = 2000m = 2 km

s₂ = 150/18 x 720 = 6000m = 6km

so this tells us that right angled triangle will be made

let x be the distance between the two buses

6² = 2² + x²

36 = 4 + x²

x² = 32

x = 5.65 km is the distance

Answer 2

Explanation:

 

V1= 10km/h = 50/18 m/s

v2 = 30 km/h = 150/18m/s

t = 12 min = 720 s

distance travel s1 = 5018×720 = 2000 m = 2 km

S2 =15018×720 = 6000 m = 6 km

TH is will make a right angleed triangle

let x is the distance between them.

6²= 2²+x²

36 = 4+x² 

=x²=32

=X=5.65Km

I hope it will help you.