two buses starts from the same bus stand at 8 am one travel at 40 km/h and the other at 50 km/h the second bus reaches the next stop at 10 am how much later will the first bus arrive?
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Answered by
3
it will arrive half hour later
abhi837:
give me answer in detail
Answered by
4
Hey!
Speed of 1st bus=40km/hr
Speed of 2nd bus=50km/hr
Time=10-8=2hrs
Distance=speed×time
1st bus = 40×2=80km
2nd bus= 50×2=100km
So clearly the total distance is 100 km which is travelled by the second bus in 2hrs.
First bus needs 20 km more to reach the distance.
Speed = 40km/hr
1/2=40km/hr
=20km half an hour
=10:30 (adding 30 to 10)
The second bus will be 30 mins delayed.
Speed of 1st bus=40km/hr
Speed of 2nd bus=50km/hr
Time=10-8=2hrs
Distance=speed×time
1st bus = 40×2=80km
2nd bus= 50×2=100km
So clearly the total distance is 100 km which is travelled by the second bus in 2hrs.
First bus needs 20 km more to reach the distance.
Speed = 40km/hr
1/2=40km/hr
=20km half an hour
=10:30 (adding 30 to 10)
The second bus will be 30 mins delayed.
Brainliest please
thankyou for giving this answer
Np
what is the meaning of Np
No problem
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