Question

two by third of a number is 20 less than the original number. find the number

Answer 1

here is ur answer
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Answer 2

Let the original number be x

$\dfrac{2}{3}$ of a number = $\dfrac{2}{3}$


According to the problem given,


$\dfrac{2}{3}$ of the jumber is less than original number by 20



A/q,

x - $\dfrac{2x}{3}$ = 20

$\dfrac{3x \: - \: 2x}{3}$ = 20

$\dfrac{x}{3}$ = 20

x = 20 × 3

x = 60




$\therefore{}$ The original number => x => 60