Math, asked by thapadipika42, 1 month ago

Two candidates contest an election .One of them secured 58% vote and won the election by a margin of 2560 votes how many votes were polled in all?



(solutions with sentence)​

Answers

Answered by keshavraj9150
1

Answer:

Since one candidate won 58% of the votes, the other won 100−58=42% of the votes.

Given,

100

58

×Total Votes−

100

42

×Total Votes=18,336

=>

100

16

×Total Votes=18,336

=>Total votes=1,14,600

So, the candiates won

100

58

×1,14,600=66,468 and =

100

42

×1,14,600=48,132 votes

hope this is helpful

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Answered by girlattitude610
0

answer:

1,14,600; 66,768 and 48,132

solution:

Since one candidate won 58% of the votes, the other won 100−58=42% of the votes.

Given,

 \frac{58}{100}  \times total \: votes -  \frac{42}{100}  \times total \: votes = 18336

  \frac{16}{100}  \times total \: votes = 18336   \\   => total \: votes = 11460

so \: the \: candiates \: won \:  \frac{58}{100}  \times 114600

66468  \: and \: =  \frac{42}{100}  \times 114600 = 48132

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