Two candidates contested an election. if one got 480 votes which are 60% of voters polled, what was the total number who voted
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480 votes --> 60%
x votes --> 100%
480/x = 60/100
480/x = 3/5
3x = 5 × 480
3x = 2400
x = 800 votes
x votes --> 100%
480/x = 60/100
480/x = 3/5
3x = 5 × 480
3x = 2400
x = 800 votes
Answered by
2
Solution :-
Let the number of total voters who voted be 'x'
One candidate got 480 votes, which is 60 % of the total voters polled
⇒ 60% of x = 480
⇒ (x*60)/100 = 480
⇒ 60x = 480*100
⇒ 60x = 48000
⇒ x = 48000/60
⇒ x = 800
Hence, the total number of voters who voted were 800.
Answer.
Let the number of total voters who voted be 'x'
One candidate got 480 votes, which is 60 % of the total voters polled
⇒ 60% of x = 480
⇒ (x*60)/100 = 480
⇒ 60x = 480*100
⇒ 60x = 48000
⇒ x = 48000/60
⇒ x = 800
Hence, the total number of voters who voted were 800.
Answer.
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