Question

two candidates fought an elecation . one of them got 55% of the total votes and won by 432 votes . what is the total number of votes polled​

Answer 1

Given :-

◉ Two candidates fought an election. One of them got 55% of the total votes and won by 432 votes.

To Find :-

◉ Total number of votes polled.

Solution :-

Let the total number of votes be x.

We are given that candidate A got 55% of x votes and candidate B got x - 55% of x.

But, It is given that candidate A won by 432 votes. which means the difference of votes they got is 432.

So, We have

⇒ Candidate A's votes - Candidate B's votes = 432

Because, Candidate A won by 432 votes, Then He/She had have got more votes than the other.

⇒ ( 55% of x ) - (x - 55% of x) = 432

⇒ 55x/100 - (x - 55x/100) = 432

⇒ 55x/100 - 45x/100 = 432

⇒ 10x/100 = 432

⇒ x = 4320

But, We assumed the total votes polled x.

∴ Total Votes Polled = 4320

Answer 2

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Given:-

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☞Total number of votes polled 1800

Step-by-step explanation:

☞Let the total vote polled be X

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SOLUTION:-

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☞One candidate got votes = 62% of X =

(62/100) xX= 0.62X

☞Thus, the other candidate got =X-0.62X =

0.38X votes

☞The first candidate won by 432 votes

☞Therefore,

0.62X-0.38X = 432

or, 0.24X = 432

or, X = 432/0.24 = 1800

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☞Therefore, total number of votes polled

.

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ANSWER:-

☞ 1800