Question

Two candles of equal height but different thickness are lightened.The first burns off in 6 hours and the second in 8 hours. How long after lighting both, will the first candle be half the height of the second candle???​

Answer 1

Answer:

Let height of each candle = x unit.

First candle burns off in 6 hours.

Second candle burns off in 8 hours.

Height of 1st candle after burning for 1 hr = x6unit

and height of 2nd candle after burning for 1 hr = x8unit

Let the required time =y hrs.

Length of 1st candle burnt after y hrs = y×x6unit

Height of 1st candle left = (x−xy6)

Length of 2nd candle burnt after y hrs = (y×x8)unit

Height of 2nd candle left = (x−xy8)

According to the question,

Height of 1st candle = 12×Height of 2nd candle

⇒x−xy6=12(x−xy8)

⇒x(1−y6)=12x(1−y8)

1−y6=12(1−y8)

⇒2−y3=1−y8

2−1= y3−y8

1 = 8y−3y24

⇒ 24=5y

⇒ y= 245

y=4.8hours=4 hours 48 minutes

hope it helps

plz mark me as brainliest answer

Answer 2

YOUR QUESTION HAS BEEN ANSWERED IN THE ATTACHED PIC.

HOPE THIS HELPS ✍