Two candles of the same height are lighted at the same time.the first is consumed in 3 hours and the second in 1 hour. Assuming that each candle burns at a constant rate,in how many hours after being lighted,the ratio between the first and second candles become 2:1
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Answer:
3,1 LCM = 3
efficiency = 1,3
Let after T hours they have ratio 2:1 left .
in T hours first burn = 1*t = t & 2nd burn = 3t
A/q,
(3-t)/(3-3t) = 2/1
3-t = 6 -6t
5t = 3
t = 3/5 hours = 36 min. (Ans.)
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