Physics, asked by durgakamdi48, 5 months ago

two capacitance c1 and c2 are combined in series if c1 =10.1 +0.1 and c2 = 5.0+0.2 calculate the combined capacitor​

Answers

Answered by khodiyargroup
0

Answer:

Two capacitors of unknown capacitances C

1

and C

2

are connected first in series and then in parallel across a battery of 100 V. If the energy stored in the two combinations is 0.045 J and 0.25 J respectively, determine the value of C

1

and C

2

. Also calculate the charge on each capacitor in parallel combination

Explanation:

When the two capacitors are in series, the equivalent capacitance, C

s

=

C

1

+C

2

C

1

C

2

When the two capacitors are in parallel, the equivalent capacitance, C

p

=C

1

+C

2

Here, U

s

=

2

1

C

s

V

2

or 0.045=0.5×

C

1

+C

2

C

1

C

2

(100)

2

or 9(C

1

+C

2

)=10

6

C

1

C

2

...(1)

Now, U

p

=

2

1

C

p

V

2

or 0.25=0.5×(C

1

+C

2

)(100)

2

or 0.02(C

1

+C

2

)×10

6

=1...(2)

(1)/(2)⇒450=10

12

C

1

C

2

...(3)

using, (2) ,(3), 0.02(C

1

+

C

1

450×10

−12

)×10

6

=1

Solving, C

1

=25+5

7

μF

C

2

=25−5

7

μF

In parallel, voltage across the capacitors is equal to the supply voltage (100 V).

Q

1

=CV=(2.5+.5

7

)mC

Q

2

=CV=(2.5−.5

7

)mC

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