Two capacitor c1= 2 micro Faraday and c2=4 micro Faraday are connected in series and a potential difference of 1200is applied across it then what is the potential difference across 2 micro Faraday
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total capacitance is 8/6
total current=1200/8/6
voltage across 2nd capacitance is
total current*capacitive reactance
total current=1200/8/6
voltage across 2nd capacitance is
total current*capacitive reactance
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