Question

Two capacitor each having capacitance C and breakdown voltage V are joined in series.

Answer 1

hey mate your answer is here,

In series arrangement at charge on each plate of each capacitor has the same magnitude the potential difference in distributed inversely in the ratio of capacitor ie,

V=V1+V2
V=2V

The equivalent capacitance C's is given by
1/Cs=1/C1+1/C2
Cs=C/2

answer is
2V and C/2

Answer 2

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HOPE IT HELPS YOU