Question

Two capacitor have a capacitance 25 microfarad when connected in parallel and 6 microfarad when connected in series.find the individual capacitance

Answer 1

Explanation:

I didn't did exact calculation I hoee you sove it

Answer 2

Answer:

The capacitances of the capacitors are 15 µF and 10 µF.

Given :

Capacitance in series(CS) = 6 µF, capacitance in parallel(CP) = 25 µF.

To find:

Find the individual capacitance of each capacitor.

Let C1 and C2 be the capacitances of the two capacitors respectively. In parallel combination,

CP = C1 + C2 = 25

In series combination,

$\frac{1}{CS}=\frac{1}{C1}+\frac{1}{C2}=\frac{C1+C2}{C1 \times C2}$,

Therefore, $CS=\frac{C1C2}{C1+C2}$

                  $6=\frac{C1C2}{25}$,

                 C1C2 = 150 ,

                 C1 (25 – C1) = 150,

                25C1 – C1 x C1= 150,

                C1 x C1 – 25C1 + 150 = 0 ,

                (C1 – 15) (C1 – 10) = 0 ,

                C1 = 15 µF or 10 µF,

               .'. C2 = 25 – C1 = 10 µF or 15 µF

Therefore, The capacitances of the capacitors are 15 µF and 10 µF.

Similar problems:

https://brainly.in/question/18590482?referrer=searchResults

https://brainly.in/question/9830962?referrer=searchResults