Question

two capacitor of 2.0microfarad and 8.0microfarad are connected in series and a potential difference of 200 volts is applied. find charge and potential difference for each capacitor​

Answer 1

Answer:

Let,

(capacitance at first capacitor is)C=2microfarad, (capacitance at second capacitor is)C'=8microfarad,and potential V=200v

Explanation:

Now,as we know

V is always constant

and from V=Q/C

now u can see my solution in above picture

Hence, q=400microcoulomb,q'=1600microcoulomb

but V-V=0

Answer 2

Explanation:

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