Question

Two capacitor of 20uf each are connected in series with battery of 10v .the total charge passing through the circuit is : 400uc Or 100uc Or 200uc Or 300uc

Answer 1

Answer:

q=c/v

for q effective =1/20 +1/20=2/20=1/10

so q=10

q=cv

q=10*10=100uc

Explanation

Answer 2

answer : total charge passing through the circuit is 100μC

two capacitors of 20μF each are connected in series with battery of 10V.

equivalent resistance when capacitors are joined in series....

1/Ceq = 1/C1 + 1/C2

⇒1/Ceq = 1/20 + 1/20 = 1/10

⇒Ceq = 10μF

total charge passing through circuit , Q = CeqV

= 10μF × 10V

= 100μC

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