Question

Two capacitor of 20uf each are connected in series with a battery of 10v . The total charge passing through the circuit : A. 400uc B.100uc C.200uc D. 300uc

Answer 1

Answer:

B

Explanation:

same capacitor in series C/2 =20/2=10

q=cv

q=10 microfarad ×10volt = 100 microcoloumb

Answer 2

The total charge passing through the circuit is :

• Given that two capacitor of 20uf each are connected in series with a battery of 10v

V = 10 v

C1 = C2 = 20 uf = 20 × 10^-6 f

• There are connected in series,

•°• 1 / Ceq = 1 / C1 + 1 / C2

1 / Ceq = C1 + C2 / C1.C2

• Ceq = C1.C2 / C1 + C2

= 20×20 / 20 + 20

= 400 / 40 = 10 uf

• We know that , C = Q / V

Q = C×V

= 10 uf × 10 v = 100 uc