Question

Two capacitor of capacitance 4mF and 6mF are connected in series. the effective

capacitance is

i) 10 mF ii) 24mF iii) 2.4 mF iv) 12 mF​

Answer 1

Answer:

iii) 2.4 mF

Explanation:

for capacitor in series,

1/Ceff=1/C1+1/C2

=1/4 + 1/6

= 10/24

Therefore, Ceff=24/10=2.4mF