Question

Two capacitors 3uF and 6uF are connected in
series with a 6V battery. Across which of the capacitors
will there be larger potential difference?​

Answer 1

Let C1=3 μF,C2=6 μF

C1 and C2 are connected in series with potential difference V=900 V acros the combination

Thus for the series combination Charge on both capacitor is same

∴C 1V1=C1V1

=2 μC ...2

also V1+V2=900 V ...3

From 2 and 3

V2=300 V and V1

=600 V

Therefore charge on each capacitor Q=300×6=600×3=1800 μC

When these capacitors are disconnected and reconnected in parallel the charge is distributed and the potential difference is same

=Q=1800 μC ...6

From 5 and 6

Q1

=600 μC and Q2

=1200 μC

Therefore the potential difference across the combination is V= 3

600

= 61200

=200 V

Ans is 200 V